2 ms·
log (D u u') = D (log u) (scale (log u) u') That doesn't look like the derivative of the natural logarithm!
by cryptonector 4y ago
log (D u u') = D (log u) (scale (log u) u')
That doesn't look like the derivative of the natural logarithm!
- pjscott 4y ago(It was fixed shortly after your comment was posted.)