3 ms·
Because there are as many subnormal values as NaN values. At least if you don't count the two 0's, which are "paired" with the two infinities.
by sjrd 4y ago
Because there are as many subnormal values as NaN values. At least if you don't count the two 0's, which are "paired" with the two infinities.
- an1sotropy 4y agooh right - sorry stupid question.