boole-and 0 0 0 1 and boole-nand 1 1 1 0 not-and While boole-and appears in the 6th (counting

boole-and 0 0 0 1 and boole-nand 1 1 1 0 not-and While boole-and appears in the 6th (counting from 0) position, it still has a binary representation here of 1, and boole-nand is (reasonably) its complement with 14. It seems the table has been reordered for some reason for this presentation. It seems to present 0-ary, 1-ary, 2-ary operations in that order, which doesn't correspond to the order of the binary representation.