There's a deterministic sequence that will beat it every time, which you can calculate as follows. - it assumes your first selection was preceeded by 5 conse

There's a deterministic sequence that will beat it every time, which you can calculate as follows. - it assumes your first selection was preceeded by 5 consecutive 'left's - each press, look at the last 5 bits you selected (for your 1st 5 selections, include those 'virtual' 5 lefts at the beginning). If you have not entered that sequence of 5 before, select 'right'. If you have entered that sequence before, pick the opposite of whatever you selected last time as your next press. RRRRRRLRRRLRLRLLRRRRLLRRLRRLRLLLRRRLLLRLRRLLRLRLRRRRRRLRRRLRLRLLRLL...