3 ms·
I'm not sure "degeneracy" is the best way to think about this. If the curvature exceeds the inverse of the offset distance, you get a cusp, and in general you n
by raphlinus 4y ago
I'm not sure "degeneracy" is the best way to think about this. If the curvature exceeds the inverse of the offset distance, you get a cusp, and in general you need to think about how to deal with those. In some cases, that will be boolean path operations (stay tuned for an update on those!). But I'm not convinced there's any shortcut where you can avoid dealing with these cases altogether.
- robocat 4y agoRalph, I presume you have seen this, but just in case… it seems like it would be something of interest to you: https://www.youtube.com/watch?v=bZbuKOxH71o https://www.youtube.com/watch?v=bZbuKOxH71o