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No, $ref(10) will return a reactive object. And 10 will be the initial value of that object. You use the object the same way you use a js variable. let st = $
by rk06 4y ago
No, $ref(10) will return a reactive object. And 10 will be the initial value of that object.
You use the object the same way you use a js variable.
let st = $ref(10)
st = st + 1 // update it and use it like if it was just "10"
But now, st is reactive.
- solardev 4y agoThank you for the explanation... I will have to learn a lot of basics, it looks like :)