The innermost of the planets is about 2.8 million kilometers away from a star with a diameter of 217,000 km, so the angle (in radians) would be about 217,000/2,

The innermost of the planets is about 2.8 million kilometers away from a star with a diameter of 217,000 km, so the angle (in radians) would be about 217,000/2,800,000 = 0.0775 radians or about 4,4 degrees. The sun is about 30 arc minutes or half a degree, so this star would have about 9 times the diameter, or 80 times the area of our sun. (Double-check: this planet is about 1/50 as far from its sun as earth is from our sun, and its sun has about 1/7 the radius of our sun. That would give a rough estimate of the relative size of that sun in the planet’s sky of 50/7, so say 7 times as large as our sun is to us) I would call that large, but not enormous. (This ignores effects on perceived size of differences in the light spectrum and brightness of the two stars and differences between the atmospheres of this planet and earth)