2 ms·
If you want to fit the area into the name you can think of it as A0 = 1/(2^0) m^2 A1 = 1/(2^1) m^2 A2 = 1/(2^2) m^2 And so on (EDIT for formatting and also
by Infernal 4y ago
If you want to fit the area into the name you can think of it as
A0 = 1/(2^0) m^2
A1 = 1/(2^1) m^2
A2 = 1/(2^2) m^2
And so on
(EDIT for formatting and also to observe a sibling post to mine is making the same point)