3 ms·
The fact that it's hard to know the inputs accurately and precisely doesn't make this any less of an equation. Given some inputs on one side, you get an output
by dakr 4y ago
The fact that it's hard to know the inputs accurately and precisely doesn't make this any less of an equation. Given some inputs on one side, you get an output on the other. You might as well call y = mx + b an estimate.