2 ms·
My impression is that PAM assumes it’s running in a Linux kernel with the typical POSIX users and permissions system. I could be misinformed though, I’ve never
by chatmasta 4y ago
My impression is that PAM assumes it’s running in a Linux kernel with the typical POSIX users and permissions system. I could be misinformed though, I’ve never actually coded anything with it.
- GekkePrutser 4y agoThat's not entirely true. PAM exists on many systems, wiyh their own codebase. FreeBSD for example has its own build which definitely doesn't presume Linux. Not sure which one macOS' implementation is based on but considering its history I would bet on one of the BSDs.