27 ms·
Its the momentum that kills you p=mV, not the kinetic energy. So I would guess that mass ia much more important.
by vihren 4y ago
Its the momentum that kills you p=mV, not the kinetic energy. So I would guess that mass ia much more important.
- Ma8ee 4y agoWhy would that be? Isn't it the energy spent tearing your body apart that is relevant?
- tzs 4y agoA typical locomotive at 1 mph has more momentum than a Ford F-150 at 45 mph, but the latter is far more likely to kill you in collision so it doesn’t look like it is momentum that kills.
- pif 4y agoYou are both wrong, It's the acceleration that kills you.
- SketchySeaBeast 4y agoAcceleration, which is caused by a transfer of energy?
- ajuc 4y agoDoubling the mass of the car assuming everything else (crumple zones etc.) stays the same - doubles the acceleration experienced by the pedestrian. X_p0 = X of the pedestrian before collision X_c0 = X of the car before collision X_p1 = X of the pedestrian after the collision X_c1 = X of the car after the collision m_ = mass v_ = velocity a_ = acceleration t = time //conservation of momentum: m_p * v_p0 + m_c * v_c0 = m_p * v_p1 + m_c * v_c1 m_p * (v_p0 - v_p1) = m_c * (v_c1 - v_c0) v_p1 - v_p0 = m_c * (v_c0 - v_c1) / m_p // a = delta v / t a = (v_p1 - v_p0)/t = m_c * (v_c0 - v_c1) / (m_p * t)