3 ms·
It's not that weird. You can consider a wave passing through a filter as a sum of two orthogonal waves, rSin(θ) + rCos(θ), θ being the angle between the light-
by yarg 4y ago
It's not that weird.
You can consider a wave passing through a filter as a sum of two orthogonal waves, rSin(θ) + rCos(θ), θ being the angle between the light-wave and the filtered angle, r being the amplitude of the wave.
One wave gets eliminated, and whatever exits exits at the only angle it can, the angle orthogonal to the filtered angle.
- yarg 4y agoI wasn't particularly clear here; but I'm not actually wrong. The reason, for example, that the 45 degree filter leaves 1/(2^.5) ~= .7 It's just the trigonometric break down of the right-angle isosceles.