3 ms·
I think the first paragraph explaining the oscillator operation is not quite right. Corrected, below, maybe. I swapped "increases" and "decreases". But the fix
by ncmncm 4y ago
I think the first paragraph explaining the oscillator operation is not quite right. Corrected, below, maybe. I swapped "increases" and "decreases". But the fix might be something different.
"In more detail, as the voltage across the crystal decreases, the transistor turns on, feeding current into the capacitors and boosting the voltage across the capacitors (and thus the crystal). But as the voltage across the crystal increases, the transistor turns off and the current sink (circle with arrow) pulls current out of the capacitors, reducing the voltage across the crystal. Thus, the feedback from the drive transistor strengthens the crystal's oscillations to keep them going."