3 ms·
Try changing line 120 to echo -e $"$(print_tick $number)\c" And it should work fine.
by Chirono 15y ago
Try changing line 120 to
echo -e $"$(print_tick $number)\c"
And it should work fine.
- rnadna 15y agoI found it necessary to escape the backslash echo -e $"$(print_tick $number)\\c"