In Go, can I declare a Foo, and deserialize into it, but instead of a Foo, it is a Bar? No. Typescript also doesn't catch cases where metaprograming is used w

In Go, can I declare a Foo, and deserialize into it, but instead of a Foo, it is a Bar? No. Typescript also doesn't catch cases where metaprograming is used when calling a function. You can put anything you want in there.