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If you have 10,000* tokens (* changed for easy square rooting), you can give 1 candidate 100 votes. Suppose you split your tokens over 100 accounts with 100 tok
by Beldin 4y ago
If you have 10,000* tokens (* changed for easy square rooting), you can give 1 candidate 100 votes.
Suppose you split your tokens over 100 accounts with 100 tokens each (100 × 100 = 10,000 - so your total number of tokens hasn't changed). If each of these accounts votes fully for the candidate, the candidate gets more votes. Specifically, each account is worth 10 votes if cast fully for one candidate, so 10 votes × 100 accounts = 1,000 votes.
And indeed, if you split your tokens over even more accounts, each token gains even more voting power. If split over 10,000 accounts, you control 10,000 votes - instead of the 100 votes you had with 1 account.
Basically, with QV, those with tokens can do tricks to gain quadratically as much power as they are supposed to have.
- tasuki 4y agoYes, this is obvious. I still can't see how the cheater with the 1000*1 votes has "achieved dominance"? > If each of these accounts votes fully for the candidate Quadratic voting kind of discourages that: the marginal vote has more utility given to another candidate. Non-cheaters will tend to spread around their votes.