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> The angles or points of the perimeter are uncountable. Surely they are countable (countably infinite). The construction algorithm given is a loop where each
by quickthrower2 4y ago
> The angles or points of the perimeter are uncountable.
Surely they are countable (countably infinite). The construction algorithm given is a loop where each loop iteration adds a finite number of edges.
- nh23423fefe 4y agoEdges aren't added. Points are added. In the limit you will have a set which you can not construct a bijection from the naturals. There is a bijection from the unit interval to the koch snowflake. So it is uncountable