3 ms·

Really? What is the additive inverse of (1, 2, 3) ∈ ℕ³ ?

• fluoridation 4y ago
  It depends on how you define addition.
  • xigoi 4y ago
    I guess you could make it a vector space through a bijection with the rational numbers, but something tells me C++ programmers don't have that in mind when writing std::vector<unsigned>. And it doesn't solve the problem that C++ “vectors” are resizable.
    • fluoridation 4y ago
      See my comment above on the subject.
• Koshkin 4y ago
  (-1, -2, -3), is it not?
  • xigoi 4y ago
    That's not a vector of natural numbers.
    • Koshkin 4y ago
      Ah, missed the N... But more interestingly, the non-negative integers 0...p-1 modulo a prime number p form a field (where -1, -2 etc. appear in a natural way), and so their tuples of some fixed length do form a vector space.