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Haskell coders have to do this often enough that there is a token that does this grouping… f $ g x = f (g x), so the expression `a b c` is still a source for am
by IHLayman 4y ago
Haskell coders have to do this often enough that there is a token that does this grouping… f $ g x = f (g x), so the expression `a b c` is still a source for ambiguity.
- deleted 4y ago[deleted]
- avgcorrection 4y ago`$` is an operator. There is no ambiguity (you might not know the precedence table but that doesn’t make it ambigious).
- pklausler 4y ago`$` = id