3 ms·
I'm not sure that claim is true. Take this experiment, where A sends B a message following two paths: /-->--B (/ and \ are mirrors) | | | | \--
by gnramires 4y ago
I'm not sure that claim is true. Take this experiment, where A sends B a message following two paths:
/-->--B (/ and \ are mirrors)
| |
| |
\--<--A
with speeds: (assume lengths are all 1m)
/--cr--B
| |
cu cu
| |
\--cl--A
The time it takes for path 1 (left,up,right) is cl+cu+cr. The time it takes for path 2 is cu. B can measure the difference cl+cu+cr-cu = cl+cr. A can compare cl+cr to cu: if cl+cr != 2cu the velocity is not isotropic. To see that's always possible, A and B can simply bounce back path 2, so B receives pulses every 2cu (and hence can measure and compare to other time intervals).
Directional speed of light would be very weird, I think it'd show up everywhere in experiments if it weren't true.
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Also, I think there's a notable distinction in physics: they are usually called postulates to distinguish from axioms. A postulate is an assumption about a physical theory (usually something simple and "beautiful" -- mathematically neat and satisfying Occam's razor); if a theory doesn't match reality, one of its postulates is incorrect. An axiom in mathematics of course can't be proven wrong. Because axioms are the basis for your mathematical theory describing reality, they can't be incorrect (as long as they form a mathematically consistent theory); the most could happen is they're insufficient to describe reality (you need other axioms and another mathematical theory), but they're not (somewhat) falsifiable in the sense of physical postulates.
- deleted 4y ago[deleted]
- kortilla 4y agoYour experiment doesn’t verify that cr = cl nor does it verify cu = cd.
- qsdf38100 4y agoI think you assume one can measure the time between two events at different locations. I believe Einstein proved you can’t because there’s no way to truly synchronize clocks at different locations. Another way to say it is that there’s no instantaneous "now" that all observers can agree on. In special relativity, "now" is meaningless. Or rather, "now" depends on the observer’s inertial frame of reference. There’s a nice diagram one can plot, with 1 dimension of space and 1 dimension of time, that shows lines of simultaneous events based on the velocity of a moving observer in another frame of reference.
- db48x 4y agoCorrect, cl+cr = 2cu is the best you can measure. But it doesn’t follow that cl = cr! Assume a linear transformation like αcl+βcr = 2cu, where α and β tell you how the speed of light varies in between left and right. We simply assume that α = β = 1.0, but what if α=½ and β=³⁄₂? Or α=2 and β=0? A long as α + β = 2.0, then everything will look exactly the same.