3 ms·

I'm very sure that's just UB. The standard requires unique representations of true and false (e.g. byte values of 1 and 0, but for all you care it could be 13 a

I'm very sure that's just UB. The standard requires unique representations of true and false (e.g. byte values of 1 and 0, but for all you care it could be 13 and 37). Converting an integer to bool (even implicitly, as in `if (3)`) is required to lead to those values in the abstract machine. If you somehow force a bool to be a different value (e.g. `*(int*)(&myBool) = 7`), that's UB.

sk0g 4y ago
It's operating on a boolean still though, here's an example - https://www.onlinegdb.com/tfHPZ_FOfY https://www.onlinegdb.com/tfHPZ_FOfY
- gpderetta 4y ago
  Line 21 and 22 are UB, so the program has no meaning according to the standard.