3 ms·
That's not what they mean there. You're confusing the evaluation of an expression to its value, with the execution of that value when the value is an IO a. In x
by edflsafoiewq 4y ago
That's not what they mean there. You're confusing the evaluation of an expression to its value, with the execution of that value when the value is an IO a. In x >> y, you can evaluate x and y in whatever order, but the program x >> y denotes always runs the program x denotes before the program y denotes. Similar to how in [x,y], x always comes before y in the list order, even if you evaluate y first.