3 ms·
It doesn't work like that because you need to include the rates of people who have a degree and whos parent's don't. CD = Child has a degree PD = Parent has a
by brutusborn 4y ago
It doesn't work like that because you need to include the rates of people who have a degree and whos parent's don't.
CD = Child has a degree
PD = Parent has a degree
Your rates would be calculated with P(CD|PD)/P(CD|notPD) = [4x20/(4x80+96A)]/[4x80/(4x80+96(100-A))]
where A = Probability of parent having a degree and child not having degree