3 ms·
Volume to surface area: for every doubling of diameter you have 1/16th the losses, before factoring in insulation. 1/16th probably sounds high, but the extra h
by samatman 4y ago
Volume to surface area: for every doubling of diameter you have 1/16th the losses, before factoring in insulation.
1/16th probably sounds high, but the extra halving is because flow rate increases as radius^4, not cubed as one might guess.