3 ms·
It ignores the mapping completely: constant.map(...) == constant Constant functors are only ever useful if you need to thread a simple value through code
by debugnik 4y ago
It ignores the mapping completely:
constant.map(...) == constant
Constant functors are only ever useful if you need to thread a simple value through code that asks for an arbitrary functor. I'd say that's rare even for abstract, type-level heavy code.