4 ms·
Isn’t every (release-mode) Microsoft CRT malloc a thin wrapper around KERNEL32!HeapAlloc (thus eventually NTDLL!RtlAllocateHeap)? CRTDLL did it, MSVCRT did it,
by mananaysiempre 4y ago
Isn’t every (release-mode) Microsoft CRT malloc a thin wrapper around KERNEL32!HeapAlloc (thus eventually NTDLL!RtlAllocateHeap)? CRTDLL did it, MSVCRT did it, UCRTBASE still seems to be doing it.
- Tringi 4y agoYes, it is.