I only skimmed through the article, but noticed it is complaining that `&mut function` is not `'static`. This is easily reproducible with: fn foo() { l

I only skimmed through the article, but noticed it is complaining that `&mut function` is not `'static`. This is easily reproducible with: fn foo() { let _: &'static mut _ = &mut foo; } And it is because while `foo` is definitely `'static`, `&mut foo` needs to be able to mutate something. The hidden secret is that `&mut foo` is desugared into something like let mut __temp = foo; &mut __temp And so it is not `'static`.