4 ms·oops. Sorry about that. Fixed. PS. Your email address is not posted either.by newt0311 18y agooops. Sorry about that. Fixed. PS. Your email address is not posted either.hhm 18y agoIsn't it something like this? 0=a-a, for all a (where a-a is actually, a+(-a)) so: mul(b,0)=mul(b,(a-a))=mul(b,a)-mul(b,a)=z-z=0newt0311 18y agopretty much.