4 ms·
> I can solve for x in x/a = b/c by cross multiplying so that xc = ab Multiply both sides by a xa/a = ba/c; a ≠ 0 Simplify x = ba/c; a ≠ 0
by metajunkies 4y ago
> I can solve for x in x/a = b/c by cross multiplying so that xc = ab
Multiply both sides by a
xa/a = ba/c; a ≠ 0
Simplify
x = ba/c; a ≠ 0