3 ms·
""[1] is not the termination byte, it's the byte after that. Its address is taken there with &, which yields a const char*. The (char *) cast is only there to
by leni536 4y ago
""[1] is not the termination byte, it's the byte after that.
Its address is taken there with &, which yields a const char*. The (char *) cast is only there to cast away const.