Mhh, while what you are saying is not wrong (though I'm not convinced about the constant thing, given everything is asymptotic), it's a bit imprecise. A more e

Mhh, while what you are saying is not wrong (though I'm not convinced about the constant thing, given everything is asymptotic), it's a bit imprecise. A more exact formulation would be m^(1+o(1)) is equal to m^(1 + eps(m)) for some eps where eps(m) -> 0 for m -> infty