No. Any constant is in O(1), but not in o(1). Specifically, f=O(g) means f is (eventually) at most Cg for a certain C, but f=o(g) means f is (eventually) at mos

No. Any constant is in O(1), but not in o(1). Specifically, f=O(g) means f is (eventually) at most Cg for a certain C, but f=o(g) means f is (eventually) at most Cg for all C. A useful, albeit not really rigorous, way to think about this is O is like ≤, while o is like <.