4 ms·
it's kinetic energy that matter at the impact. def: E=mv^2/2 assuming car 2 is 2x heavier than car 1, to have the same kinetic energy, their respective velocit
by apetrov 4y ago
it's kinetic energy that matter at the impact.
def: E=mv^2/2
assuming car 2 is 2x heavier than car 1, to have the same kinetic energy, their respective velocities should be:
m2 = 2 * m1
2m1 v2^2/2 = m1 * v1^2/2
2 * v2^2 = v1^2
v2 = v1/sqrt(2) ~ 0.7
another word 2000lbs car driving at 100mph has the same kinetic energy as 4000lbs driving at 70mph