4 ms·
This feels a bit like cherry picking? I mean, the heaviest EV is the Hummer EV at 9000lbs compared to the original Hummer at 8000lbs. Most other EVs are of cour
by strongpigeon 4y ago
This feels a bit like cherry picking? I mean, the heaviest EV is the Hummer EV at 9000lbs compared to the original Hummer at 8000lbs. Most other EVs are of course heavier but not garishly so (e.g. Tesla Model 3 coming at around 4000 lbs, which is about the same as a BMW M3).
The point about the acceleration being stronger is fair, but I don't think this means overall EVs are much more dangerous than ICE cars.
- quesera 4y ago(Deleted naïve physics of uncommon case.)
- dr_orpheus 4y agoBut the acceleration that you are concerned about here is the acceleration (or deceleration) of a car from it's current speed to the speed after the crash. That's the acceleration that has an impact on humans. A more accurate equation to look at would be kinetic energy = 1/2mv^2. More energy a car has in hitting something the worse the outcome will be. Now you can say that cars with greater acceleration may be more likely to be driving faster, but it's not a direct correlation of acceleration of a car to the force of impact of the car.
- deleted 4y ago[deleted]
- xdavidliu 4y ago> A more accurate equation to look at would be kinetic energy = 1/2mv^2. More energy a car has in hitting something the worse the outcome will be. worse it will be for who, for people in the car or for the something?
- apetrov 4y agoit's kinetic energy that matter at the impact. def: E=mv^2/2 assuming car 2 is 2x heavier than car 1, to have the same kinetic energy, their respective velocities should be: m2 = 2 * m1 2m1 v2^2/2 = m1 * v1^2/2 2 * v2^2 = v1^2 v2 = v1/sqrt(2) ~ 0.7 another word 2000lbs car driving at 100mph has the same kinetic energy as 4000lbs driving at 70mph