3 ms·
That is probably a reason big-O is used, the big-O definition which says that they most be upper-bounded by a linear multiplier. So even if the second and third
by erk__ 4y ago
That is probably a reason big-O is used, the big-O definition which says that they most be upper-bounded by a linear multiplier. So even if the second and third multiplication is faster it will not change the asymptotic behavior.