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Yes. Eg if you look at Java try-with-resources there is an exact scope during which resources live and can be used. At the end of the scope the .close() method
by Matthias247 4y ago
Yes. Eg if you look at Java try-with-resources there is an exact scope during which resources live and can be used. At the end of the scope the .close() method will be called.
For C++ and Rust there might not be a well defined scope since objects can be „moved“. Eg a method constructing an object can return it to the caller without the destructor being called.
- jolux 4y agoIt's well-defined, it's just more flexible than Java. The difference is that returning a value moves it, and resources are owned by the creating scope by default. Java doesn't have the same concept of ownership, or rather, you can't move values in Java.