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You should be able to simply use Json.Deserialize<T>() ? The beauty of types in this case is that the JSON structure has a natural way to be expressed in C#… w
by setr 4y ago
You should be able to simply use Json.Deserialize<T>() ?
The beauty of types in this case is that the JSON structure has a natural way to be expressed in C#… we just need to utilize it
Or a JsonNode if you don’t know the structure