I cant really check this right now but doesnt $(exit 5) just spawn a subshell which exits with 5 which is visible by the parent script you just source your sh

I cant really check this right now but doesnt $(exit 5) just spawn a subshell which exits with 5 which is visible by the parent script you just source your show-error.sh in? Try to subshell the source too like (. ./show-error.sh)