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No it doesn't. It's perfectly explained by you becoming entangled with the system when you interact with it. No spooky action at a distance needed. The wavefu
by Schroedingersat 4y ago
No it doesn't.
It's perfectly explained by you becoming entangled with the system when you interact with it. No spooky action at a distance needed.
The wavefunction exists. Entanglement exists. Why is it so hard to extend that concept to the experimenter?
- astrange 4y agoThat’s superdeterminism (the version of it Sabine likes), but most scientists won’t accept it because they hear you as saying they can’t do reproducible experiments.
- Schroedingersat 4y agoNo it's not, it's many worlds. It's completely local and says nothing about free will or causality. Step 1) Entangle pair. Parts of wavefunction with up-down and down-up exist. Step 2) Lab A interacts with pair, they either get entangled with the up-down pair or the down-up pair, or any other subset of the wavefunction. Step 3) Lab B interacts with any part of the Lab A+pair wavefunction. When they do, they find that, astonishingly, the part of the wavefunction they find themselves entangled with when they speak to Lab A is the same part of the wave function they find themselves entangled with based on their measurements. No new entities are posited, no new mechanism is posited, no assertions are made about wavefunctions vanishing upon interaction. It's the simplest possible claim. The only effect it has on whether or not you can do reproducible experiments is the entropy in the subset of the wavefunction you can potentially interact with went up.