4 ms·

> much more complete combustion of the fuel More complete combustion of the fuel they intend to burn. But since their mixture is very fuel rich, they emit a lo

> much more complete combustion of the fuel More complete combustion of the fuel they intend to burn. But since their mixture is very fuel rich, they emit a lot of methane. No amount of engine design can eliminate that methane from their exhaust.

AnimalMuppet 4y ago
Why is their mixture very rich? Wouldn't a balanced mixture give them more energy, and therefore more thrust?
- HarryHirsch 4y ago
  You are looking for maximum impulse, not maximum energy. If you run fuel-rich, the extra fuel converts heat into impulse, it acts as reaction mass, so to speak. Water injection in jet engines works along the same principles, convert heat into volume of vapour.
  - AnimalMuppet 4y ago
    OK, but couldn't you do the exact same thing by running lean? Then the extra oxygen would convert heat into impulse. Or, as you said, by steam injection? (But then you'd need an extra tank for the steam, so that's probably less than optimal...) (I'm not saying they're wrong. I'm asking for an explanation.)
    - HarryHirsch 4y ago
      The real-life application for an oxygen-rich mixture is a cutting torch, you really don't want that. Also, maximum impulse means high exhaust velocity, that means exhaust gasses with low molecular mass. Oxygen wouldn't qualify.
      - ncmncm 4y ago
        Yes, burning away the interior surface of your combustion chamber runs into a resource limit pretty quickly, shortly followed by rapid uncontrolled dissociation. The exhaust colors leading up to that are often pretty, and finally dramatic. There have been rockets that ran lean during the first few seconds, deliberately eroding away a layer of the combustion chamber, to get higher-mass particles into the exhaust while trying to clear the launch tower. The higher-mass exhaust particles gives you less efficiency but more thrust, which is most important just then.
    - nickff 4y ago
      Running lean makes the combustion hotter, and melts the chambers on a rocket.
      - avmich 4y ago
        > Running lean makes the combustion hotter Not necessarily, unburned oxygen will reduce average temperature.
    - QuadmasterXLII 4y ago
      You ask a good question! When you dig into it, the goal of almost all modern rocket engine optimization is to create a mixture rich in hot hydrogen. For thermodynamic reasons, smaller molecules move faster at a given temperature, hydrogen is spectacularly smaller than any other molecule, and the most important quality of a rocket engine is its exhaust velocity.
      - ncmncm 4y ago
        Among the most important qualities of a rocket engine is its exhaust velocity, which determines its efficiency, delta-V per unit mass of fuel/oxidizer burned. Not exploding is probably the actual most important quality. You don't really start tuning for efficiency until you have got that one nailed. Sometimes absolute thrust is more important than efficiency. Perhaps surprisingly, efficiency can be traded off for thrust by getting heavier molecules into the exhaust. They are coming out slower than the naked protons, but not as many times slower as the ratio of their mass to the protons'.
        deleted 4y ago
        [deleted]
- pfdietz 4y ago
  LOX-hydrocarbon engines typically operate a bit fuel rich. This is because at stoichiometric ratios, the flame is so hot that you lose significant energy to dissociation. Therefore, diluting the gas slightly by a fuel that adds hydrogen, thereby reducing the average molecular weight, can win back enough of that energy that you come out ahead (higher Isp). Interestingly, Hydrogen Peroxide/hydrocarbon engines optimize to stoichiometric, since the extra water from the peroxide dilutes and cools the gas enough that this effect no longer is a win. For this reason, the jets from such engines have little unburned fuel and are almost invisible.
  - avmich 4y ago
    > Interestingly, Hydrogen Peroxide/hydrocarbon engines optimize to stoichiometric Really? It can be challenging to find pairs where fuel-rich doesn't give some better Isp, right?
    - pfdietz 4y ago
      Yes. It's because of all the dilution peroxide already causes. The effect is illustrated by that weird British launcher, the Black Arrow, that used peroxide as the oxidizer. The picture of it taking off looks like something Photoshopped, with the vehicle just sort of levitating above the launch pad. https://www.edinburghlive.co.uk/news/edinburgh-news/black-arrow-historic-uk-rocket-15729810 https://www.edinburghlive.co.uk/news/edinburgh-news/black-ar...
  - hoseja 4y ago
    I thought the main reason to cool down exhaust with fuel-rich mixture was to not literally melt/burn the engine/nozzle.
pfdietz 4y ago
I don't think there's much methane in the exhaust at all. Carbon monoxide, yes, hydrogen, yes, but the methane should disappear at the temperature of the gas in the thrust chamber, even if it's not fully oxidized.
fransje26 4y ago
The design exists. H2/O2. And you get the best usable specific impulse.. With some cryogenic downsides..

AnimalMuppet 4y ago

Why is their mixture very rich? Wouldn't a balanced mixture give them more energy, and therefore more thrust?

HarryHirsch 4y ago
You are looking for maximum impulse, not maximum energy. If you run fuel-rich, the extra fuel converts heat into impulse, it acts as reaction mass, so to speak. Water injection in jet engines works along the same principles, convert heat into volume of vapour.
- AnimalMuppet 4y ago
  OK, but couldn't you do the exact same thing by running lean? Then the extra oxygen would convert heat into impulse. Or, as you said, by steam injection? (But then you'd need an extra tank for the steam, so that's probably less than optimal...) (I'm not saying they're wrong. I'm asking for an explanation.)
  - HarryHirsch 4y ago
    The real-life application for an oxygen-rich mixture is a cutting torch, you really don't want that. Also, maximum impulse means high exhaust velocity, that means exhaust gasses with low molecular mass. Oxygen wouldn't qualify.
    - ncmncm 4y ago
      Yes, burning away the interior surface of your combustion chamber runs into a resource limit pretty quickly, shortly followed by rapid uncontrolled dissociation. The exhaust colors leading up to that are often pretty, and finally dramatic. There have been rockets that ran lean during the first few seconds, deliberately eroding away a layer of the combustion chamber, to get higher-mass particles into the exhaust while trying to clear the launch tower. The higher-mass exhaust particles gives you less efficiency but more thrust, which is most important just then.
  - nickff 4y ago
    Running lean makes the combustion hotter, and melts the chambers on a rocket.
    - avmich 4y ago
      > Running lean makes the combustion hotter Not necessarily, unburned oxygen will reduce average temperature.
  - QuadmasterXLII 4y ago
    You ask a good question! When you dig into it, the goal of almost all modern rocket engine optimization is to create a mixture rich in hot hydrogen. For thermodynamic reasons, smaller molecules move faster at a given temperature, hydrogen is spectacularly smaller than any other molecule, and the most important quality of a rocket engine is its exhaust velocity.
    - ncmncm 4y ago
      Among the most important qualities of a rocket engine is its exhaust velocity, which determines its efficiency, delta-V per unit mass of fuel/oxidizer burned. Not exploding is probably the actual most important quality. You don't really start tuning for efficiency until you have got that one nailed. Sometimes absolute thrust is more important than efficiency. Perhaps surprisingly, efficiency can be traded off for thrust by getting heavier molecules into the exhaust. They are coming out slower than the naked protons, but not as many times slower as the ratio of their mass to the protons'.
      - deleted 4y ago
        [deleted]
pfdietz 4y ago
LOX-hydrocarbon engines typically operate a bit fuel rich. This is because at stoichiometric ratios, the flame is so hot that you lose significant energy to dissociation. Therefore, diluting the gas slightly by a fuel that adds hydrogen, thereby reducing the average molecular weight, can win back enough of that energy that you come out ahead (higher Isp). Interestingly, Hydrogen Peroxide/hydrocarbon engines optimize to stoichiometric, since the extra water from the peroxide dilutes and cools the gas enough that this effect no longer is a win. For this reason, the jets from such engines have little unburned fuel and are almost invisible.
- avmich 4y ago
  > Interestingly, Hydrogen Peroxide/hydrocarbon engines optimize to stoichiometric Really? It can be challenging to find pairs where fuel-rich doesn't give some better Isp, right?
  - pfdietz 4y ago
    Yes. It's because of all the dilution peroxide already causes. The effect is illustrated by that weird British launcher, the Black Arrow, that used peroxide as the oxidizer. The picture of it taking off looks like something Photoshopped, with the vehicle just sort of levitating above the launch pad. https://www.edinburghlive.co.uk/news/edinburgh-news/black-arrow-historic-uk-rocket-15729810 https://www.edinburghlive.co.uk/news/edinburgh-news/black-ar...
- hoseja 4y ago
  I thought the main reason to cool down exhaust with fuel-rich mixture was to not literally melt/burn the engine/nozzle.

pfdietz 4y ago

I don't think there's much methane in the exhaust at all. Carbon monoxide, yes, hydrogen, yes, but the methane should disappear at the temperature of the gas in the thrust chamber, even if it's not fully oxidized.

fransje26 4y ago

The design exists. H2/O2. And you get the best usable specific impulse.. With some cryogenic downsides..