3 ms·
3.7v but they charge to 4.2v, but it doesn't matter, because the dynamo is going to produce variable voltages and currents. so it's going to go through a boost
by naikrovek 4y ago
3.7v but they charge to 4.2v, but it doesn't matter, because the dynamo is going to produce variable voltages and currents. so it's going to go through a boost-buck converter and that will output 4.2v at whatever current it can.
- rhn_mk1 4y agoThe peak voltage of the battery might be 4.2V, but the average will be around 3.6 nevertheless. The voltage before the energy enters the battery doesn't change the calculation of battery capacity (and its time to discharge) anyway. EDIT: now I noticed that the calculation is about charging, rather than discharging. 4.2V makes better sense in that case.