3 ms·
As someone who has used this (to enable a single function to be called either preemptively or cooperatively by a surrounding VM)... It's not leaky. To be fran
by throwawaymaths 5y ago
As someone who has used this (to enable a single function to be called either preemptively or cooperatively by a surrounding VM)... It's not leaky. To be frank, until you've actually done it, it's hard to see.
- layer8 5y agoSection 4 of the article I linked demonstrates how it’s leaky. Admittedly just in special scenarios, but it means that the mechanism isn’t fully transparent.