3 ms·
I apparently entered my test cases wrong in lots of interesting ways. I think I've actually found essentially the same solution you have, it turns out I had th
by nialo 15y ago
I apparently entered my test cases wrong in lots of interesting ways. I think I've actually found essentially the same solution you have, it turns out I had the exceptions and the actual solution backwards:
n avargl qrterr ebgngvba naq n ersyrpgvba nobhg, nf sne nf V pna gryy nal, yvar guebhtu gur bevtva frrzf gb tvir gur evtug erfhyg.
Are we sure this is the correct meaning for "A = -B", where A and B are matrices? Some things I've read seem to be saying that that should be equivalent to AB = identity matrix, rather than Av = -1(Bv), where v is some vector.
- gruseom 15y agoIt's the correct meaning, as indicated by the solution on p. 430. You're thinking not of -B but of the inverse of B, which is denoted B^-1 ("B to the power of -1") and when multiplied by B gives I.