Note that pi is not known to have this property, but it is expected to be true. Also note that it is not true that any transcendental number must have every fi

Note that pi is not known to have this property, but it is expected to be true. Also note that it is not true that any transcendental number must have every finite sequence of digits in its decimal expansion. A common counter-example would be a Liouville number: sum k=1->inf (1/10^k!) = 0.11000100000000000000000100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001... Which is proven to be transcendental [0], but still does not contain a digit "2" in its decimal expansion, so therefore it does not contain all finite sequences of numbers. You were probably thinking of Normal numbers [1], pi is widely believed to be a normal number. [0] https://en.wikipedia.org/wiki/Liouville_number https://en.wikipedia.org/wiki/Liouville_number [1] https://en.wikipedia.org/wiki/Normal_number https://en.wikipedia.org/wiki/Normal_number