4 ms·
I don't need to run that to know that it calls foo exactly once. Function designators decay to a pointer to the function if they are not the subject of the & o
by caf 15y ago
I don't need to run that to know that it calls foo exactly once. Function designators decay to a pointer to the function if they are not the subject of the & or sizeof operators, so the string of *s simply converts it repeatedly between a function designator and a function pointer.