The third answer's explanation could be better than whats given : " That is, whenever an array appears in an expression, the compiler implicitly generates a po

The third answer's explanation could be better than whats given : " That is, whenever an array appears in an expression, the compiler implicitly generates a pointer to the array's first element, just as if the programmer had written &a[0] " http://c-faq.com/aryptr/aryptrequiv.html http://c-faq.com/aryptr/aryptrequiv.html Also remember that much fun could be had by studying the pre-processor up close .. another source of mind-bending fun.