3 ms·
So for question 4 it was a matter of realizing that the type for &x is a pointer to an array of 5 ints: int (*y)[5]; y = &x; printf("%p, %p\n", y, y+1);
by mtoddh 15y ago
So for question 4 it was a matter of realizing that the type for &x is a pointer to an array of 5 ints:
int (*y)[5];
y = &x;
printf("%p, %p\n", y, y+1);