Not the person you asked, but, P(9,9,9,9,9,9 | Not random ) > average over all values of (sequence) of P((sequence) | Not random ) (under some reasonable assu

Not the person you asked, but, P(9,9,9,9,9,9 | Not random ) > average over all values of (sequence) of P((sequence) | Not random ) (under some reasonable assumptions about how likely you consider different processes to be the process producing the output) While P(9,9,9,9,9,9 | random ) = average over all values of (sequence) of P((sequence) | random ) Therefore, P( Not random | 9,9,9,9,9,9 ) > P( Not random )