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There's a few layers of complexity here. The first is lvalues. In compiler jargon, an lvalue is a kind of object that can have a value stored to it. And you ca
by jcranmer 5y ago
There's a few layers of complexity here.
The first is lvalues. In compiler jargon, an lvalue is a kind of object that can have a value stored to it. And you can usually represent it as the address of some memory location [1]. Of course, bitfields break this representation: you need to know what the bit offset and bit size of the field you're storing is (as well as the signedness).
The next level of complexity is the conditional operator. This means that, when conditional operators yield lvalues [2], you now end up in a situation where the lvalue now has a conditional bit offset and bit size within the address. Or maybe one leg of the expression returns a bit-field and the other leg returns a regular int lvalue. Imagine how complex your datastructure needs to be to represent an lvalue during this code generation phase.
[1] Not all lvalues need to have memory locations. But if you're writing a C compiler, it's an easy first approximation to give every variable, even those marked register, some memory location and rely on an optimization pass to convert stack memory locations into register locations, rather than keeping track of this information when the frontend does code generation.
[2] As mentioned elsewhere, conditional operators in C do not yield lvalues. But conditional operators in C++ do.