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It is always possible to generate a collision for any hash function since they are not injective by definition.
by l33t2328 5y ago
It is always possible to generate a collision for any hash function since they are not injective by definition.
- eyelidlessness 4y agoMy point wasn’t to address whether any hashing technique might be collision-free, but that assessing that fact is not a good metric for the fitness of a given hashing technique.